Mathematics
01.07.2020 15:50
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Graphing Quadratic Functions f(x) = 2r2 - 5x + 1, -1 (x, y) f(x) = -2x2 + 3x + 4,-2.5

Graphing Quadratic Functions
f(x) = 2r2 - 5x + 1, -1 (x, y)
f(x) = -2x2 + 3x + 4,-2.5 (x, y)
(d) f(x) = -4xΒ² + 4x - 1,-1 (x, y)

I don’t understand anything can anyone help?
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helpplz5725
helpplz5725
4,4(37 marks)

Horizontal axis with 1, 2, and 3 standard deviations above the mean are 51.6, 56.2, 60.8

Horizontal axis with 1, 2, and 3 standard deviations below the mean are 42.4, 37.8, 33.2

Step-by-step explanation:

A data set has a normal distribution with a mean of 47 and a standard deviation of 4.6

Mean, M β‡’ 47Standard deviation β‡’ 4.6

From this information, you have to scale the horizontal axis with the mean of this distribution and values at 1, 2, and 3 standard deviations above and below the mean.

Horizontal axis with 1, 2, and 3 standard deviations above the mean :

1 standard deviation above the mean β‡’ M + SD

β‡’ 47 + 4.6 = 51.6

2 standard deviations above the mean β‡’ M + 2SD

β‡’ 47 + (2 Γ— 4.6) = 56.2

3 standard deviations above the mean β‡’ M + 3SD

β‡’ 47 + (3 Γ— 4.6) = 60.8

Horizontal axis with 1, 2, and 3 standard deviations below the mean :

1 standard deviation below the mean β‡’ M - SD

β‡’ 47 - 4.6 = 42.4

2 standard deviations below the mean β‡’ M - 2SD

β‡’ 47 - (2 Γ— 4.6) = 37.8

3 standard deviations below the mean β‡’ M - 3SD

β‡’ 47 - (3 Γ— 4.6) = 33.2

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