Mathematics
31.07.2021 02:32
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Given that z is a standard normal random variable, find z for each situation (to

Given that z is a standard normal random variable, find z for each situation (to 2 decimals). the area to the left of z is .2119.
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yoridff
yoridff
4,5(57 marks)

Given that z is a standard normal random variable,

the area to the left of z is .2119.

The area to the left of z is given and we need to find out the z-score

To find z we use z-score table

z- score table is attached below.

We look at the z- score that has value 0.2119

From the table we can see that 0.2119 has z-score -0.80

the area to the left of -0.80 is .2119.



Given that z is a standard normal random variable, find z for each situation (to 2 decimals). the ar
londonpaige
londonpaige
4,4(8 marks)
81^5 = 3,486,784,401
3,486,784,401 / = X
X = 1,162,261,467
(I think anyways)

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