Chemistry
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Gas mixture composition of 78.0% nitrogen, 17.0% oxygen, % argon,% carbon dioxide.

Gas mixture composition of 78.0% nitrogen, 17.0% oxygen, % argon,% carbon dioxide. find the mass of nitrogen?
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20068513
20068513
4,5(55 marks)

 

Best  Total number of moles n = PV/RT = (12.5atm x 10L)/(0.082 x 298K) = 5.1154 mole  

30g of oxygen = 30g/32g/mol = 0.94 mole. Also 30g of nitrogen = 30g/28g/mole = 1.07 moles.  

Let the number of moles of CO2 be = c,  

0.94 + 1.07 + c = 5.1154. Hence c = 3.105 mole = number of moles of CO2  

Mass of CO2 = 3.105 moles x 44g/mole = 136.62g ~ 137g

evazquez
evazquez
4,8(71 marks)
Please answer please please thank you

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