For the equilibrium: 2 NO​ (g) ​ ⇌ N​ 2(g)​+ O​ 2(g)​at 300 K, the equilibrium constant,

The concentrations of at equilibrium are 0.112 M, 0.112 M  and 0.260 M

Explanation:

Moles of = 1.45 mole

Moles of   = 1.45 mole

Volume of solution = 6.00 L

Initial concentration of =

Initial concentration of =

The given balanced equilibrium reaction is,

Initial conc.          0 M             0.242 M              0.242 M  

At eqm. conc.     (2x) M      (0.242-x) M        (0.242-x) M

The expression for equilibrium constant for this reaction will be,

Now put all the given values in this expression, we get :

By solving the term 'x', we get :

x = 0.130

Thus, the concentrations of at equilibrium are :

Concentration of = (0.242-x) M  = (0.242-0.130) M = 0.112 M

Concentration of = (0.242-x) M  = (0.242-0.130) M = 0.112 M

Concentration of = 2x M = = 0.260 M

Put the values in numerical order before trying to find the median. The median is the number in the middle of an ordered set of values. The median must be calculated by finding the mean of the two middle points when there is an even number of

data points.

Explanation:

The median is simply the middle number in an ordered set and is unaffected by outliers. If there are two middle points in an ordered set, then the average of the two numbers is the median.