a)P = 78.21 KN
b)L=128.285 mm
Explanation:
Given that
E= 116 GPa
σ = 259 MPa
a)
A= 302 mm²
Lets take load P can applied without plastic deformation
We know that
P = σ A
P = 259 x 302 N
P = 78218 N
P = 78.21 KN
b)
Lo= 128 mm
Lets take final length = L
Change in length ΔL
Strain ε = ΔL/L
ε = σ/E
By putting the values
ΔL=0.285 mm
The final length L
L = ΔL + Lo
L = 0.285 + 128
L=128.285 mm
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