Mathematics
02.07.2020 10:29
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Find the slope of the line that contains points (a,c) and (m,c)

Find the slope of the line that contains points (a,c) and (m,c)
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Rocket8025
Rocket8025
4,7(16 marks)
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~{{ a}} &,&{{ c}}~) 
%  (c,d)
&&(~{{ m}} &,&{{ c}}~)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{c-c}{m-a}\implies \cfrac{0}{m-a}\implies 0
amazinga
amazinga
4,8(11 marks)

1/9 = 0.1111 = 11.11% probability that the first die is a 6 given that the minimum of the two numbers is a 2.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Minimum of the two numbers is 2.

Event B: First die in a 6.

Fair dice:

Each throw has 6 equally likely outcomes. Thus, in total, there are 6^2 = 36 possible outcomes.

Minimum of the two numbers is a 2.

(2,2), (2,3), (3,2), (2,4), (4,2), (2,5), (5,2), (2,6), (6,2).

9 total outcomes in which the minumum of the two numbers is a two, which means that:

P(A) = \frac{9}{36}

Minimum of the two numbers is a 2, and the first die is a 6.

Only one possible outcome, (6,2). So

P(A \cap B) = \frac{1}{36}

Probability that the first die is a 6 given that the minimum of the two numbers is a 2.

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{1}{36}}{\frac{9}{36}} = \frac{1}{9} 0.1111

1/9 = 0.1111 = 11.11% probability that the first die is a 6 given that the minimum of the two numbers is a 2.

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