Find (12y + 20y2 – 2) + (-13y2 + y - 10). Write your answer in standard form.

7y²+13y-12

Step-by-step explanation:

20y²+12y-2-13y²+y-10

7y²+13y-12

551.82feet tall

Step-by-step explanation:

WE are given the following from the question;

Distance of me from the bottom of the building = 1300feet (adjacent)

Angle of elevation = 23 degrees

Required

Height (opposite)

Using the SOH CAH TOA identity

Tan theta = opp/adj

Tan 23 = H/1300

H = 1300tan23

H = 1300(0.4245)

H = 551.82feet

Hence the building is 551.82feet tall