Mathematics
15.03.2020 12:22
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F(t)= 102,000/1+4400e^-t

F(t)= 102,000/1+4400e^-t
F(t)= 102,000/1+4400e^-t
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genyjoannerubiera
genyjoannerubiera
4,5(75 marks)

Beginning (t=0) population with flu is 23.

After 4 weeks, population with flu is 1250.

After an infinite amount of weeks, the population witf flu is 102000

Step-by-step explanation:

First question asks you to replace t with 0 because it says beginning.

102000/(1+4400e^-0)=102000/(1+4400)=102000/4401=23.17655 approximately. To nearest whole number this is 23.

After 4 weeks means we replace t with 4:

102000/(1+4400e^-4)

Calculator time:

1250.17142 which to nearest whole number is 1250

If t is super large, then e^-t is super close to 0.

So the limiting number is

102000/(1+4400×0)=102000/1=102000

christianfielding336
christianfielding336
4,4(17 marks)
Hello,

x²+12=7x
==>x²-7x+12=0
==>x²-3x-4x+12=0
==>x(x-3)-4(x-3)=0
==>(x-3)(x-4)=0
==>x=3 or, x=4

Answer D

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