F(−2)=3 f′(−2)=4 g(4)=5 g′(4)=2 The point (−2,4) lies on the curve in the xy -plane

F(−2)=3 f′(−2)=4 g(4)=5 g′(4)=2

The point (−2,4) lies on the curve in the xy -plane given by the equation f(x)g(y)=17−x−y , where f is a differentiable function of x and g is a differentiable function of y . Selected values of f , f′ , g , and g′ are given in the table above. What is the value of dydx at the point (−2,4) ?