Mathematics
11.02.2022 15:13
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Enter the coefficients of the fifth taylor polynomial t5(x) for the function f(x)

Enter the coefficients of the fifth taylor polynomial t5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. t5(x)= + (x−1)+ (x−1)2+ (x−1)3+ (x−1)4+ (x−1)5. note: this exercise gives a method for writing a polynomial in powers of x−1 instead of powers of x. this may be useful, for example, if you are interested in the values of the polynomial near x=1 .
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alanaruth3389
alanaruth3389
5,0(12 marks)

The coefficients are 3, 2, -6, -2, 2, and 1 and this can be determined by using the series formula.

Given :

\rm f(x) = x^5-3x^4+2x^2+5x-2b= 1\rm T_5(x) = (x -1)^1+ (x-1)^2+ (x-1)^3+ (x-1)^4+ (x-1)^5

The formula of the series is given below:

\rm T(x) = \sum^{\infty}_{n=0} \dfrac{f^n(b)}{n!}(x-b)^n

Now, determine the value of \rm f'(1).

\rm f'(x) = 5x^4-12x^3+4x+5

\rm f'(1) = 5 - 12 + 4 + 5 = 2

Now, determine the value of \rm f''(1).

\rm f''(x) = 20x^3-36x^2+4

\rm f"(1) = 20 - 36 + 4 = -12

Now, determine the value of \rm  f'''(1).

\rm f'''(x) = 60x^2-72x

\rm f'''(1) = 60 - 72 = - 12

Now, determine the value of \rm f''''(1).

\rm f''''(x) = 120x-72

\rm f''''(1) = 48

The coefficients are 3, 2, -6, -2, 2, and 1 and this can be determined by using the series formula.

For more information, refer to the link given below:

link

jetblackcap
jetblackcap
4,5(10 marks)

Compute the necessary values/derivatives of f(x) at x=1:

f(1)=3

f'(1)=2

f''(1)=-12

f'''(1)=-12

f^{(4)}(1)=48

f^{(5)}(1)=120

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) f(x) at x=1 by

T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5

T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5

###

Another way of doing this would be to solve for the coefficients a,b,c,d,e,g in

f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5

by expanding the right hand side and matching up terms with the same power of x.

jennyhoang4330
jennyhoang4330
4,9(93 marks)
Cylinder Formula: V = 3.14 * r² * h   
Cone Formula: V = 3.14 * r² * h/3
                                                                      Hint: 15/3 is 5
Cylinder: V = 3.14 * 4² * 5                         Cone: V = 3.14 * 4² * 15/3
                 V = 3.14 * 16 * 5                                    V = 3.14 * 16 * 15/3
                 V = 50.24 * 5                                          V = 50.24 * 15/3 
                 V = 251.2 in.³                                          V = 251.2 in.³
They both have the same volume.

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