4.32% of the bottles will have more than 12.86 ounces.
Step-by-step explanation:
This is a normal distribution problem with
Mean = ฮผ = 6 ounces
Standard deviation = ฯ = 0.4 ounce
Let the z-score of 4.32% of the bottles be z' and the corresponding ounces be x'
The z-score for any is the value minus the mean then divided by the standard deviation.
z' = (x' - ฮผ)/ฯ
P(x > x') = P(z > z') = 0.0432
Using the normal distribution table
P(z > z') = 1 - P(z โค z') = 0.0432
P(z โค z') = 1 - 0.0432 = 0.9568
z' = 1.715
1.715 = (x' - 6)/0.4
x' - 6 = 4(1.715)
x' = 6 + 6.86 = 12.86 ounces.
4.32% of the bottles will have more than 12.86 ounces.
Hope this Helps!!!