Mathematics
11.09.2021 18:44
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Draw the line of reflection that reflects ABC onto AA B C . y 7 Pro 6- 5- Ted 4

Draw the line of reflection that reflects ABC onto AA'B'C'. y
7
Pro
6-
5-
Ted
4
B'3
B
2
N
+
-7 -6
-5 -4 -3 -2
2 3
5
6
7
СТ
-2
C
-3-
Do 4 problems OOOO
Draw the line of reflection that reflects ABC onto AA'B'C'.

y
7
Pro
6-
5-
Ted
4
B'3
B
2
N
+
-7 -6
Show Answers
gloverj9639
gloverj9639
4,4(58 marks)

Line of reflection → x = 1

Step-by-step explanation:

Coordinates of B → (3, 2)

Coordinates of B' → (-1, 2)

If point B is reflected across a vertical line x = a, both the points B and B' will be equidistant from the line of reflection.

Coordinates of the midpoint of the segment joining B and B'

= (\frac{x_+x_2}{2},\frac{y_1+y_2}{2})

= (\frac{3-1}{2},\frac{2+2}{2})

= (1, 2)

Line of reflection will pass through this midpoint (1, 2)

Therefore, equation of the line of reflection will be,

x = 1


Draw the line of reflection that reflects ABC onto AA'B'C'.

y
7
Pro
6-
5-
Ted
4
B'3
B
2
N
+
-7 -6
-
tommy6668
tommy6668
4,6(33 marks)

Step-by-step explanation:

base = 19 inch

height = 14 inch

area \: of \: triangle \:  =  \frac{1}{2} \: ( base)(height) \\  \\ area \: of \: triangle \:  =  \frac{1}{2} (19)(14)

area of triangle = 133 inch² !!


Area of a triangle with a 19 inch base and 14 inch height

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