a) 265.2 MPa
b)-172.8 MPa
c) -0.6541
d) 438 MPa
Explanation:
we know that
..............(1)
.................(2)
solving equ (1) and equ (2) we get
= 265.2 MPa
= -172.8 MPa
stress ratio =
= = -0.6515
now stress range = -
= 265.2 -(-172.8) = 438 MPa
Explanation:
Here,we've been given that,
Initial velocity (u) = 0 m/s (as it starts from rest)Distance (s) = 145 mFinal velocity (v) = 420 m/sWe've to find the acceleration of the object. By using the third equation of motion,
→ v² - u² = 2as
→ (420)² - (0)² = 2 × a × 145
→ 176400 - 0 = 290a
→ 176400 = 290a
→ 176400 ÷ 290 = a
→ 608.275862 m/s² = a