Consider the following list. list = {5, 11, 25, 28, 45, 78, 100, 120, 125}; suppose

To search 110 is in list we key comparisons binary search will make are option

(A) 3

Explanation:

First the start =0 and end =8 and midindex=4.

So 110 will be compared to element at index 4 that is 45 since 110 is greater than 45 so start will be updated as start=midindex +1.

start=5 , end =8 and midindex=6.

Element at index 6 is 100 so 110 will be compared to 100 since it is greater so again start will be updated midindex+1.

start=7,end=8 midindex=7

element at index 7 is 120 so 110 will be compared to 120 since it is smaller than 120 end will be updated as midindex -1.

start=7,end=6

Now we have start > end .So the loop will finish execution.

Comparison made are 3.

Not applicable.

Explanation:

You'll have to provide the multiple choice options that are likely associated with this question in order to receive an answer.