Consider the diagram and the derivation below. given: in △abc, ad ⊥ bc derive a

Consider the diagram and the derivation below. given: in △abc, ad ⊥ bc derive a formula for the area of △abc using angle c. it is given that in △abc, ad ⊥ bc. using the definition of sine with angle c in △acd results in sin(c) = . using the multiplication property of equality to isolate h, the equation becomes bsin(c) = h. knowing that the formula for the area of a triangle is a = bh is and using the side lengths as shown in the diagram, which expression represents the area of △abc? bsin(c) absin(c) cbsin(c) hbsin(c) mark this and return