Mathematics
15.07.2021 12:39
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Can you guys help with 1-3

Can you guys help with 1-3
Can you guys help with 1-3
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kdd46
kdd46
4,8(7 marks)

1. y = 1/3x - 1

2. y = 2/5x

3. y = x + 8

Step-by-step explanation:

Generally, we have the equation of a straight line as;

y = mx + c

where m is the slope and c is the y-intercept

So, we have the following based on the supplied values;

1. y = 1/3x - 1

2. y = 2/5x

3. y = x + 8

parisw8
parisw8
4,9(44 marks)

The rocket reached its maximum height at 2 seconds.

The maximum height of the rocket is 36 yards.

Step-by-step explanation:

Quadratic equation:

In the format

h(t) = ah^{2} + bh + c

The maximum height happens at the instant of time:

t_{v} = -\frac{b}{2a}

The maximu height is h(t_{v})

In this question:

H(t) = -3t^{2} + 12t + 24

So a = -3, b = 12, c = 24

When did the rocket reach its maximum height?

t_{v} = -\frac{12}{2*(-3)} = 2

The rocket reached its maximum height at 2 seconds.

What was the maximum height of the rocket?

H(2).

H(2) = -3*2^{2} + 12*2 + 24 = 36

The maximum height of the rocket is 36 yards.

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