Physics
20.05.2023 11:37
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Can someone please help me ​
Can someone please help me ​
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dbhuggybearow6jng
dbhuggybearow6jng
4,6(76 marks)

F = 153 N

\theta = 11.3°

Explanation:

Let us define first our directional convention. Anything pointing up or to the right is considered positive and anything pointing down or to the left is considered negative. Now let's look at the components F_{x} and F_{y}:

F_{x} = 350 N - 200 N = 150 N

F_{y} = 180 N - 150 N = 30 N

The magnitude of the resultant force F is given by

F = \sqrt{F_{x}^{2}+F_{y}^{2}}

\:\:\:\:\:\:= \sqrt{(150\:N)^{2}+(30\:N)^{2}}

\:\:\:\:\:\:=153\:N

To find the direction \theta, we use

\tan \theta = \dfrac{F_{y}}{F_{x}}=\dfrac{30\:N}{150\:N}=0.2

or

\theta = \tan^{-1}(0.2) = 11.3°

purplebandit96
purplebandit96
4,9(13 marks)
If we now heat the mixture to 50 °C, the remaining 9 g of glucose will dissolve. At the new temperature, the solubility limit in 100 mL of water is 244 g glucose. With only 100 g of glucose dissolved, the solution is now unsaturated.
If we next cool the mixture back to 25 °C, 9 g of glucose should precipitate from solution.
If glucose crystals do not form, the system has more dissolved glucose (100 g) than it can hold at 25 °C (91 g). We have a supersaturated solution.
The first step in the formation of crystals is nucleation. This is when the solute molecules arrange themselves to form crystals.
Sometimes this happens at once. If it doesn't, we have a supersaturated solution. This is an unstable situation.
A piece of dust or a small crystal of the solute, a seed crystal, provides a template for crystallization of the excess solute. The excess solute starts to form crystals on the nuclei.

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