Can someone do 11??? Please help I don’t want to fail my class

Recall that the tangent of an angle is equal to the ratio of the opposite over adjacent sides

tan(angle) = opposite/adjacent

For reference angle Y, the opposite side is XZ = 6 and the adjacent side is XY = 7, so,

tan(Y) = XZ/XY = 6/7

For tan(Z), things will swap. The opposite side is now XY = 7 and the adjacent side is now XZ = 6

tan(Z) = XY/XZ = 7/6

We do not use the hypotenuse sqrt(85) at all in this problem because the tangent ratio does not involve the hypotenuse.

f(-5)= 90, g(7)= -3x+4

Step-by-step explanation:

First Solve f(x)

f(x)= 3×^2-3x

Plug in -5 to the x

3(5)^2-3(-5)

f(x)= 90

Then Solve g(x)

g(x)=-3x+4

Plug in the 7 in the x

g(x)=-3x+4

g(x)=17