Chemistry
20.03.2022 12:13
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Calculate the vapor pressure of a solution containing 24.6 g of glycerin (c3h8o3)

Calculate the vapor pressure of a solution containing 24.6 g of glycerin (c3h8o3) in 134 ml of water at 30.0 ∘c. the vapor pressure of pure water at this temperature is 31.8 torr. assume that glycerin is not volatile and dissolves molecularly (i.e., it is not ionic) and use a density of 1.00 g/ml for the water.
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marionyallop9205
marionyallop9205
4,6(42 marks)

Answer : The vapor pressure of a solution is, 30.687 torr

Explanation :

First we have to calculate the moles of glycerin.

\text{Moles of }C_3H_8O_3=\frac{\text{Mass of }C_3H_8O_3}{\text{Molar mass of }C_3H_8O_3}=\frac{24.6g}{92.09g/mole}=0.267moles

Now we have to calculate the mass of water.

\text{Mass of }H_2O=\text{Density of }H_2O\times \text{Volume of }H_2O

\text{Mass of }H_2O=(1.00g/ml)\times (134ml)=134g

Now we have to calculate the moles of water.

\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{134g}{18g/mole}=7.444moles

Now we have to calculate the mole fraction of water.

\text{Mole fraction of water}=\frac{\text{Moles of water}}{\text{Moles of water}+\text{Moles of glycerin}}

\text{Mole fraction of water}=\frac{7.444mole}{7.444mole+0.267mole}=0.965

Now we have to calculate the vapor pressure of the solution.

According to the Raoult's law,

p_A=X_A\times p^o_A

where,

p_A = vapor pressure of solution = ?

p^o_A = vapor pressure of pure water= 31.8 torr

X_A = mole fraction of water = 0.965

Now put all the given values in this formula, we get the vapor pressure of solution.

p_A=0.965\times 31.8\text{ torr}

p_A=30.687\text{ torr}

Therefore, the vapor pressure of a solution is, 30.687 torr

andrew8228
andrew8228
4,6(64 marks)
The force would be a balanced force because both of the people are using the same force so it would not move.

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