Chemistry
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Caffeine is 4.9 times more soluble in propanol than in a salt-water solution. Assume

Caffeine is 4.9 times more soluble in propanol than in a salt-water solution. Assume you extracted 200 mg of caffeine from tea leaves into 80.00 mL of a salt-water solution. You then extracted this aqueous phase three times with 50.00 mL of propanol each time.
How much caffeine will be in the organic phase?
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130004979
130004979
4,7(5 marks)

NaOH

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2NBr3 + 3NaOH β€”> N2 + 3NaBr + 3HOBr

The limiting reactant can be obtained as follow:

From the balanced equation above,

2 moles of NBr3 reacted with 3 moles of NaOH.

Therefore, 40 moles of NBr3 will react with = (40 x 3)/2 = 60 moles of NaOH.

From the above calculations,

A higher amount of NaOH i.e 60 moles than what was given from the question i.e 48 moles is required to react completely with 40 moles of NBr3. Therefore, NaOH is the limiting reactant and NBr3 is the excess reactant.

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