Physics
25.04.2021 23:41
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Block A is initially moving to the right at 6.00 m/s, while block B is initially

Block A is initially moving to the right at 6.00 m/s, while block B is initially at rest. The surface they move on is level and frictionless. What is the velocity of the center of mass of the two blocks after the blocks collide
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trujillo03
trujillo03
4,6(70 marks)

Complete question:

Block A on the left has a mass of 1.0 kg, Block B on the right has a mass of 3.0 kg.

Block A is initially moving to the right at 6.00 m/s, while block B is initially at rest. The surface they move on is level and frictionless. What is the velocity of the center of mass of the two blocks after the blocks collide

The velocity of center mass of the two blocks after collision is 1.5 m/s to the right.

Explanation:

Let the mass of block A = m₁ = 1 kg

Let the mass of block B = m₂ = 3kg

initial velocity of block A, u₁ = 6 m/s

initial velocity of block B, u₂ = 0

let the velocity of center mass of the blocks after collision = v

Apply the principle of conservation of linear momentum for inelastic collision (the two blocks sticked together after collision);

m_1u_1 + m_2u_2 = v(m_1+m_2)\\\\m_1u_1 + m_2(0) = v(m_1+m_2)\\\\m_1u_1 = v(m_1+m_2)\\\\v = \frac{m_1u_1}{m_1+m_2}\\\\v= \frac{1*6}{1+3}\\\\v= \frac{6}{4}\\\\v= 1.5 \ m/s \ \ \ to \ the \ right

v = 1.5 m/s to the right

Therefore, the velocity of center mass of the two blocks after collision is 1.5 m/s to the right.

loredobrooke9929
loredobrooke9929
4,5(70 marks)

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Explanation:

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