Physics
11.01.2021 20:26
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Azebra starts from rest and accelerates at 1.9 m/s, how far has the zebra gone after

Azebra starts from rest and accelerates at 1.9 m/s, how far has the zebra gone after 5 seconds
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dev804
dev804
4,5(33 marks)

23.8 m

Explanation:

The distance travelled by the zebra can be calculated by using the equation:

d=ut+\frac{1}{2}at^2

where

u is the initial velocity

t is the time

a is the acceleration

For this zebra,

u = 0 since it starts from rest

a=1.9 m/s^2 is the acceleration

Substituting t = 5 s, we find the distance travelled by the zebra:

d=0+\frac{1}{2}(1.9)(5)^2=23.8 m

michaelchavez6959127
michaelchavez6959127
5,0(77 marks)

C. in addition of 200 J of thermal energy in a loss of 350 J of kinetic energy

i took the test

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