Physics
01.09.2020 10:50
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Athin uniform wire is bent into a rectangle. the short, vertical sides are of length

Athin uniform wire is bent into a rectangle. the short, vertical sides are of length a, and the long, horizontal sides are of length b.

if the total mass is 41.00 grams, a = 45.00 cm and b = 70.00 cm, what is the moment of rotational inertia about an axis through one of the vertical wires?
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asdf334asdf334
asdf334asdf334
4,6(3 marks)

I = 0.00801 kg.m^2

Explanation:

The rectangle is composed by 4 pieces:

2*ma + 2*mb = 0.041 Kg   Since the wire is uniform, we can calculate each partial mass ma and mb:

ma = \frac{La*m}{La+Lb}=0.00802kg

mb = \frac{Lb*m}{La+Lb}=0.0125kg

The total inertia is given by:

I=2*Ib+ma*Lb^2  where Ib=mb/3*Lb^2

The inertia is therefore:

I=2*mb/3*Lb^2+ma*Lb^2

I = 0.00801 kg.m^2

jamaal97
jamaal97
5,0(50 marks)
The acceleration is inmx/s2

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