Athin stream of water flows smoothly from a faucet and falls straight down. at one

The formulas are, v1d1² = v2d2² (1) h = (v2²-v1²)/2g (2) Given that, v1 = 1.71 m/s we assume that the stream has decreased by a factor d2 =0.805d1 then, v1d1² = v2 (0.805d1)² cancelled both side d1² then we get, v1 = v2 (0.805)² v1 = v2 (0.648025) Sub v1 = 1.71, 1.71 = v2 (0.648025) v2 = 1.71/0.648025 v2 = 2.638787083831642 v2 = 2.64 m/s The vertical distance formula, h = (v2²-v1²)/2g We know that value of gravity constant is 9.8 m/s² h = {(2.64)² - (1.71)²)/2(9.8) h = {(6.9696) - (2.9241)}/19.6 h = (4.0455)/19.6 h = 0.2064030612244898 h = 0.21 cm Therefore, the vertical distance h = 0.21 cm.

The induced current in the loop is 20 A

Further explanation

Lenz's law said that when EMF is generated by the change in magnetic flux the polarity of the induced EMF produces an induced current. It induced electric current flows in a direction such that the current opposes the change that induced it

The square loop shown in the figure moves into a 0.80T magnetic field at a constant speed of 10m/s. The loop has a resistance of 0.10Ω, and it enters the field at t = 0s. Find the induced current in the loop as a function of time. Give your answer as a graph of I versus t from t = 0s to t = 0.020s.

B = 0.8 T

L = 5 cm

v = 10 m/s

R = 0.10 Ω

I = ?

∈=E

Ф=o

The induced current in the loop is 20 A. According to Lenz's law I goes to counterwise

Learn moreLearn more about magnetic field Learn more about constant speed Learn more       about the induced current Answer details

Grade: 8

Subject:  physics

Chapter:  Lenz's law

Keywords:   magnetic field, constant speed, the induced current, loop, resistance