Mathematics
19.02.2023 05:58
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Astudent is studying a population of 100 daylilies by the roadside. the plants in

Astudent is studying a population of 100 daylilies by the roadside. the plants in this population are genetically variable. the variance in seed production in this population (population a) is 20. she then takes one plant and creates cuttings to make a genetically identical population and plants the identical population (b) next to population a. the variance in seed production in population b is 5. what is the broad sense heritability in seed production for the roadside population of daylilies?
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jaydenromero31
jaydenromero31
4,7(68 marks)

broad sense heritability = 0.75

Step-by-step explanation:

Step 1: Variables

phenotypic variation (Vp)

genotype variation (Vg)

environment variation (Ve)

broad sense heritability (H)

Step 2: Formulas:

H = Vg / Vp

Vp = Vg + Ve

Vg = Vp - Ve

Step 3: Given data

Vp = 20

Ve = 5

Step 4: Computation

Vg = 20 - 5 = 15

H = 15 / 20

H = 0.75

Hope this helps!

nolz4066
nolz4066
5,0(46 marks)

.125

Step-by-step explanation:

The volume of a cube is found by

V = s^3  where s is the side length

V = .5 ^3

V =.125 m^3

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