a
The image distance is
b
The image is real and inverted because the image distance in positive
c
The image is located to the left side
d
The magnification is
e
The image height is
f
The image is real and inverted because the image distance in positive
Explanation:
In the Solution We assume that the lens is converging
The lens Equation is mathematically represented as
Where f is the focal length = 4.20 cm
v is the image distance = ?
u is the object distance = + 1.5 (since is to the left i.e the source of light )
Making v the subject in the equation above
Mathematically magnification is represented as
Mathematically the image height is represented as
Where is the image height
is the object height = 1.5