The length of the inclined plane is 63.53 m and the time taken by the skier to cover the distance is 7.0588 sec.
Given to us
Velocity, u = 3.0 m/s
Angle of Inclination = 10"
Velocity of skier at the bottom, v = 15 m/s
What is the acceleration of the skier on the inclined plane?We know that acceleration of the skier on the inclined plane can be given as,
a = g sin(θ)
a = g sin(10)
a= 9.81 x 0.1736
a = 1.70 m/sec²
What is the length of the incline?We know that according to the third equation of motion
Substitute the values,
Using the first equation of motion,
Hence, the length of the inclined plane is 63.53 m and the time taken by the skier to cover the distance is 7.0588 sec.
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acceleration of the skier on the inclined plane is given by
now by equation of kinematics
so the length of inclined plane will be 63.53 m
Part b)
Time to reach the bottom will be given by
so it will take 7.06 s to reach the bottom