Mathematics
15.12.2022 01:51
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Area under the curve (application of integration) y=2x^2-8x+9; [3,4] solve step
Area under the curve (application of integration)
y=2x^2-8x+9; [3,4]
solve step by step
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solve step by step
baidentheodore9750
4,6(50 marks)
It’ll be 0.73913 to the nearest tenth
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