Chemistry
19.08.2020 04:19
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answer the following and round to the correct number of significant figures (don

answer the following and round to the correct number of significant figures (don't forget units).
a) 0.02123 m + 1.12 m + 0.00123 m =
b) 2.3 cm - 1.23 cm + 120 cm =
c) 25,430 km - 3,500 km + 200 km =
d) (1.21 x 105 ) x (2.6 x 103 ) =
e) 7.13 mm x 9.1 mm =
f) 3.0 cm x 8.222 cm =
g) 4.1 g ÷ 0.121 cm =
h) 0.413 ÷ (9.212 x 103 ) =
i) (12.1 cm - 4.15 cm) / 35.64 g =
j) (11.00 m - 3.356 m) x 45.1 kg /35.64 s =
k) 73.0 x 1.340 x (25.31 – 1.6) =
l) (418.7 x 31.8) / (19.27 – 18.98) =
Show Answers
elizabethxoxo3271
elizabethxoxo3271
4,6(46 marks)

a) 0.02123 m + 1.12 m + 0.00123 m =  1.14246m it can be round off as 1.1425m

b) 2.3 cm - 1.23 cm + 120 cm = 121.07 cm it can be round off as 121.1 cm

c) 25,430 km - 3,500 km + 200 km =  22130 km

d) (1.21 x 105 ) x (2.6 x 103 ) =  34023.99 it can be round off as 34024

e) 7.13 mm x 9.1 mm =  64.883 mm it can be round off as 65 mm

f) 3.0 cm x 8.222 cm =  24.666 cm it can be round off as 25 cm

g) 4.1 g ÷ 0.121 cm =  33.8842 g/cm it can round off as 34 g/cm

h) 0.413 ÷ (9.212 x 103 ) =   0.00043527

i) (12.1 cm - 4.15 cm) / 35.64 g =  0.223063973 cm/g

j) (11.00 m - 3.356 m) x 45.1 kg /35.64 s =  9.672962963 m kg/s

k) 73.0 x 1.340 x (25.31 – 1.6) =  2319.3122

l) (418.7 x 31.8) / (19.27 – 18.98) = 45912.62069 45912.6207

lilyplant4289
lilyplant4289
4,6(39 marks)

-205.7 kJ

Explanation:

if ur a connexus kid i just took this too lol

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