Mathematics
01.03.2021 20:57
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Andrea purchased 2.8 pounds of bananas that cost $0.60 per pound and a bag of apples

Andrea purchased 2.8 pounds of bananas that cost $0.60 per pound and a bag of apples that cost $3.50. How much did she spend in all?
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861819
861819
4,8(48 marks)

Total cost = $5.18.

Step-by-step explanation:

Given the following data;

A pound of banana = $0.60

Quantity of banana = 2.8 pounds

Bag of apples = $3.50

To find the amount spent on banana;

Cost of banana = Quantity of banana * cost of each pound of banana

Cost of banana = 2.8 * 0.6 = $1.68

Total amount spent on banana = $1.68

Therefore, the total amount spent by Andrea on both banana and apples;

Total cost = cost of apple + cost of banana

Total cost = $3.5 + $1.68

Total cost = $5.18.

infoneetusinghoyg22o
infoneetusinghoyg22o
4,7(40 marks)
To solve this problem you must apply the proccedure shown below:
 1. You have the following expresssion given in the problem above: b^24a^2−4ab+b^2+a−b^2a−b 
 2. Therefore, you must factor the common terms to simplify the expression above, as following:
 ba(b^23-b-4)+b(b-1)+a
 Then, as you can see, the answer is: ba(b^23-b-4)+b(b-1)+a

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