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07.02.2022 07:53
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An Ocean Thermal Energy Conversion (OTEC) power plant built in Hawaii in 1987 was

An Ocean Thermal Energy Conversion (OTEC) power plant built in Hawaii in 1987 was designed to operate between the temperature limits of 86°F at the ocean surface and 41°F at a depth of 2100 ft. About 13,300 gpm of cold seawater was to be pumped from deep ocean through a 40-in-diameter pipe to serve as the cooling medium or heat sink. If the cooling water experiences a temperature rise of 6°F and the thermal efficiency is 2.5 percent, determine the amount of power generated. Take the density of seawater to be 64 lbm/ft3. Also, take the specific heat of water to be c = 1.0 Btu/lbm·°F.
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nataliahenderso
nataliahenderso
4,4(45 marks)

power generated = 307.84 Kw

Explanation:

The Given data

Tk = 86 f = 303.15k

To = 41 f = 278.15k

thermal efficiency ( n ) = 0.025

Q = 13300 gpm = 0.84 m^3/sec

C = 1.0 Btu/Ibmf

density of seawater ( d ) = 64 Ibm/ft3 = 1025.18 kg/m^3

rise in temp = 6 f

we have to make assumptions

steady statefluid is in compressible and constant

first we calculate

mass flow rate of water ( Mw )

Mw = density of seawater * Q

      =  64 * 13300 * 1/7.4804

      = 113790 Ibm/min  = 1896.51 Ibm/sec

therefore the rejection of the cooling water will be

 = mass flow rate * C * rise in temperature

= 1896.51 * 1.0 * 6

= 11379.06 BTU/s (Qout)

Determine the amount of power generated using thermal efficiency formula

n = \frac{W}{Qout + W}  

W = power generated

n = thermal efficiency

Qout = rejection of cooling water

0.025 = \frac{W}{11379.06 + W}

W = 0.025 W + 284.48

W ( 1 - 0.025 ) = 284.48

therefore   W = 284.48 / 0.975

W = 291.77 BTU/s

note : 1 kw = 0.9478 BTU/s

            x   = 291.77 BTU/s

W in kw ( x ) = 291.77 / 0.9478 = 307.84 Kw

deg12
deg12
4,8(26 marks)

D. It must be capable of sending high-resolution photos back to earth.

Explanation:

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