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An object travels around a circle of radius r with constant speed. If s is the distance

An object travels around a circle of radius r with constant speed. If s is the distance traveled in time t around the circle and is the central angleâ (in radians) swept out in timeâ t, then the linear speed of the object is vâ and the angular speed of the object is â.
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ajbrock1004
ajbrock1004
4,4(83 marks)

\frac{1}{2}mR^2\omega^2

Explanation:

The rotational kinetic energy of an object is given by KE_r=\frac{1}{2}I\omega^2, where I is the object's moment of inertia/rotational inertia and \omega is the object's angular speed.

What we're given:

The object's moment of inertia: I=MR^2The object's radius, mass, and angular speed: R, m, \omega, respectively

Since no numerical value is given for any of these, it is implied the desired answer will be an equation in terms of the variables given.

Substituting I=MR^2:

KE_r=\boxed{\frac{1}{2}mR^2\omega^2}

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