An object of mass 2.00 kg is held at a position a, a vertical height of 20.0 m above

find the time for the object to fall from position A to position B. You can use \[x = \frac{1}{2}at^2\]to do so. \(x\) represents the distance traveled, \(a\) is the acceleration (here due to gravity, so use the value provided for \(g\)), and \(t\) is the time. When you have found the time required for the object to fall from position A to position B, you can use \[v = at\] to calculate the speed. Again, \(a=g\) and \(t\) is the value you found in the first part ;)

Which planet is an inner planet, and which one is an outer planet? Explain your answer

Explanation: