Physics
24.08.2021 05:12
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An ice skater has a moment of inertia of 5.0 kg · m2when her arms are outstretched,

An ice skater has a moment of inertia of 5.0 kg · m2when her arms are outstretched, and at this time she is spinning at 3.0 rev/s. if she pulls in her arms and decreases her moment of inertia to 2.0 kg · m2, how fast will she be spinning?
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erickamiles1797
erickamiles1797
5,0(80 marks)

Explanation:

Given

Initial Moment of Inertia I_1=5 kg-m^2

initial Spin N_1=3 rev/s

\omega _1=2\pi N_1=2\pi 3=6\pi rad/s

Final Moment Moment of Inertia I_2=2 kg-m^2

Conserving Angular momentum

L_1=L_2

I_1\omega _1=I_2\omega _2

5\times 6\pi=2\times \omega _2

\omega _2=15\pi rad/s

N_2=\frac{\omega _2}{2\pi }

N_2=\frac{15\pi }{2\pi}=7.5 rev/s

bri9263
bri9263
4,6(40 marks)
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