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An elevator and its load have a combined mass of 1200 kg. find the tension in the

An elevator and its load have a combined mass of 1200 kg. find the tension in the supporting cable when the elevator, originally moving downward at 10 m/s, is brought to rest with constant acceleration in a distance of 62 m. (hint: if the elevator is slowing down and moving down then the upward force is greater)
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joelpimentel
joelpimentel
4,6(13 marks)

12739.74 N

Explanation:

m = Mass of load + Mass of elevator = 1200 kg

s = Displacement of the elevator = 62 m

g = Acceleration due to gravity = 9.81 m/s²

u = Initial velocity = 10 m/s

v = Final velocity = 0

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-10^2}{2\times 62}\\\Rightarrow a=-0.80645\ m/s^2

Tension on the cable

T=m(g-a)\\\Rightarrow T=1200(9.81-(-0.80645))\\\Rightarrow T=12739.74\ N

Here, as the elevator is going down the acceleration due to gravity and the acceleration will be subtracted.

Hence,  the tension in the supporting cable is 12739.74 N

Aethis
Aethis
4,8(25 marks)
Question is not clear

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