Physics
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An electric dipole, consisting of charges each of magnitude 2.11 nC and separated

An electric dipole, consisting of charges each of magnitude 2.11 nC and separated by 8.37 micrometers, is in an electric field of strength 1578 N/C. What is the magnitude of the difference in potential energy (in Joules) corresponding to dipole orientations parallel to and anti-parallel to the electric field
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ghari112345
ghari112345
4,4(13 marks)

54*10^-13 J

Explanation:

given:

charge =2.11 nC

distance=8.37*10-6

electric field intensity=1578 N/C

solution:

dipole moment magnitude=q.2a

                                            =2.11 nC*2*8.37*10-6

                                            =18*10^-15

potential energy of dipole = -P*E

                                           = -P*E*cos Ф

for parallel orientation, Ф=0

potential energy = -18*10^-15*300*cos 0

                             =-54*10^-13 J

for perpendicular orientation, Ф=90

potential energy = -18*10^-15*300*cos 90

                             =0

           difference =0-(-54*10^-13 )J

                            =54*10^-13 J

welathyasf
welathyasf
4,6(83 marks)

A chemical change results from a chemical reaction, while a physical change is when matter changes forms but not chemical identity. Examples of chemical changes are burning, cooking, rusting, and rotting. Examples of physical changes are boiling, melting, freezing, and shredding. Often, physical changes can be undone, if energy is input.

Explanation: hope this helps have a good day

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