Mathematics
28.01.2022 00:04
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An archeologist finds a skull in Piltdown Park in England. He discovers that only

An archeologist finds a skull in Piltdown Park in England. He discovers that only 3% of the original amount of carbon-14 is still present in the skull. If the decay constant for carbon-14 is 11×10−5 , estimate the age of the skull.
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myaj580
myaj580
4,7(32 marks)

3.19\times10^4\text{ seconds} or 8.86 hours

Step-by-step explanation:

The quantity of material left after a time, t, during a radioactive decay is given by

N = N_0 e^{-\lambda t}

N_0 is the initial quantity, \lambda is the decay constant

\dfrac{N}{N_0} = e^{-\lambda t}

\dfrac{N}{N_0} is the fraction left.

Substituting given values from the question,

0.03 = e^{-\lambda t}

\ln 0.03 =-\lambda t

t = \dfrac{\ln 0.03}{-\lambda}

t = \dfrac{-3.507}{-11\times10^{-5}} = 3.19\times10^4\text{ seconds}

This is about 8.86 hours

jetthehawk9861
jetthehawk9861
4,5(28 marks)

The answer is line segment

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