Mathematics
02.01.2021 23:09
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Alma is estimating the proportion of students in her school district who, in the

Alma is estimating the proportion of students in her school district who, in the past month, read at least 1 book. From a random sample of 50 students, she found that 32 students read at least 1 book last month. Assuming all conditions for inference are met, which of the following defines a 90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month?
a. b. c. d. e.
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CarlyAnnn9949
CarlyAnnn9949
4,6(87 marks)

D

Step-by-step explanation:

Confidence interval is written as

Sample proportion ± margin of error

Margin of error = z × √pq/n

Where

z represents the z score corresponding to the confidence level

p = sample proportion. It also means probability of success

q = probability of failure

q = 1 - p

p = x/n

Where

n represents the number of samples

x represents the number of success

From the information given,

n = 50

x = 32

p = 32/50 = 0.64

q = 1 - 0.64 = 0.36

To determine the z score, we subtract the confidence level from 100% to get α

α = 1 - 0.9 = 0.1

α/2 = 0.01/2 = 0.05

This is the area in each tail. Since we want the area in the middle, it becomes

1 - 0.05 = 0.95

The z score corresponding to the area on the z table is 2.05. Thus, confidence level of 90% is 1.645

Therefore, the 90% confidence interval is

0.64 ± 1.645√(0.64)(0.36)/50

mat1413
mat1413
4,5(86 marks)

625,604

Step-by-step explanation:

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