Physics
04.11.2020 16:08
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Alan leaves Los Angeles at 8:00 a.m. to drive to San Francisco, 400 mi away. He

Alan leaves Los Angeles at 8:00 a.m. to drive to San Francisco, 400 mi away. He travels at a steady 46.0 mph . Beth leaves Los Angeles at 9:00 a.m. and drives a steady 55.0 mph .How long does the first to arrive have to wait for the second?
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cxbelle
cxbelle
4,4(10 marks)

25 min, 48 sec

Explanation:

Alan:

t = d/v

  = 400 mi / 46 mph = 8.70 hr

So it took Alan 8.70 hrs; from 8 am, that's 4:42 pm that he arrives.

t = d/v

  = 400 mi / 55 mph = 7.27 hr

So it took Beth 7.27 hrs; from 9 am, that's 4:16:12 that she arrives.

4:42 - 4:16:12 = 25.8 minutes = 25 minutes, 48 sec

Jbullon119
Jbullon119
4,5(75 marks)

The air that is inside a ship is much less dense than water. That's what keeps it floating! ... The closer the total density of the ship is to the density of the same volume of water, the greater the amount of the ship that will be in the water.

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