Air in a rigid tank is initially at 320 k and 130 kpa. heat is added until the final

Change in entropy is 0.8712 kJ/kgK

Given:

Initial Temperature, T = 320 K

Initial Pressure, P = 130 kPa

Final Pressure, P' = 438 kPa

Solution:

Here, a rigid tank is considered, therefore, the volume of the tank is constant and for a process at constant volume:

Pressur, P ∝ Temperature, T

Therefore,

Now, change in entropy is given by:

Therefore, change in entropy is 0.8712 kJ/kgK

A Jacob's ladder or magic tablets or Chinese blocks or klick-klack toy

i knew it as klick klack toy

Explanation: