Physics

31.05.2023 01:40

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Adocking shuttle needs to decelerate at a very specific rate, given by a=bt2a=bt2

Adocking shuttle needs to decelerate at a very specific rate, given by a=bt2a=bt2 . if the shuttle is moving at 800m/s800m/s and begins at 30km away, how long will it take to dock?

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siri5645

4,4(53 marks)

as it is given here

a = bt^2

by integrating both sides

$v_f - v_i = \frac{bt^3}{3}$

as finally it has to stop

$800 = \frac{bt^3}{3}$

2400 = bt^3

also we know that

$v = 800 - \frac{bt^3}{3}$

integrating both sides

$x = 800 t - \frac{bt^4}{12}$

$30000 = 800 t - \frac{2400*t}{12}$

30000 = 800t - 200t

t = 50 s

so it will take t = 50 s to cover this distance

kargarzadehsm

4,4(50 marks)

$C. \: only \: defective \: spherical \: mirrors$

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Adocking shuttle needs to decelerate at a very specific rate, given by a=bt2a=bt2

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