Acommon belief is that a hole in a jet plane can suck a person out. on an episode
a typical jet plane travels at 532 mph at a cruising altitude of 31500 ft. the windows on a jet plane measure 14.0 in × 14.0 in. calculate the force exerted on such a window as the plane flies at 31500 ft above the sea level. assume the density and pressure of air at 31500 ft is 0.429 kg/m3 and 276 mbar but the interior of the plane remains pressurized to atmospheric pressure, that is, 1 atm.
calculate the fractional difference between this force and the weight wman,n of a typical adult male (185 lb).
f/wman =
how would you respond to adam and jaime?
a. there is no need to perform the experiment; it is impossible for a person to be sucked out of a plane.
b. my calculation does not prove that such an event cannot happen; you will need to perform the experiment.
F / Wman = 11 and option B
Explanation:
Pressure is the relationship between the force and the area where it is applied, in the case of the airplane the difference between the outside and inside pressure is
Let's start reducing it to units, you have a very strong mix.
Pint = 1 atm (10⁵ Pa / atm) = 1 10⁵Pa
Pext = 276 mB = 276 10⁻³ Bar (10⁵Pa / 1Bar) = 0.273 10⁵ Pa
L = 14.0 in (2.54 10⁻² m / 1 in) = 35.56 10⁻² m
W = 185 lb (4,448 N / 1lb) = 822.9 N
ΔP = Pint - Pext
ΔP = 1 10⁵ -0.276 10⁵
ΔP = 0.724 10⁵ Pa
P = F / A
F = P A
A = L * L
A = (35.56 10⁻²)²
A = 1.26 10⁻¹ m²
F = 0.724 10⁵ 1.26 10⁻¹
F = 0.912 10⁴ N
This force steers the plane out
The rational difference
F / Wman = 0.912 104 / 822.9
F / Wman = 11
F = 11 Wman
The force due to the pressure difference is 11 times greater than the weight of the man, so that it does not come out it has to have a very strong friction and be supported by something to equalize the force, I would carry out the experiment, option B
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Explanation:
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