Physics
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Aclose coiled helical spring of round steel wire 10 mm diameter having 10 complete
Aclose coiled helical spring of round steel wire 10 mm diameter having 10 complete turns with a mean radius of 60 mm is subjected to an axial load of 200 n. determine the deflection of the spring. c = 80 kn/mm2.
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mjlchance367
5,0(67 marks)
The deflection of the spring is 34.56 mm.
Explanation:
Given that,
Diameter = 10 mm
Number of turns = 10
Load = 200 N
We need to calculate the deflection
Using formula of deflection
Put the value into the formula
Hence, The deflection of the spring is 34.56 mm.
calmicaela12s
4,9(20 marks)
In order to calculate the value of force without radius, you may need the circumference whose formula is C=2πr. You can also find this force by calculating just acceleration using the formula: And this is also called Newton’s second law of motion, which can be calculated by entering acceleration and mass of the object.
hope this is what you want
Explanation:
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