Given: Takeoff Speed (u) = 28 m/s
Final velocity (v) = 0.0 m/s
Acceleration (a) = 1.9 m/s²
To calculate: The minimum length of runway (s) =?
Solution: Apply 3rd kinematic equation of motion
v² = u² - 2as
Or, s = ( u² - v²) / 2 a
Or, s = ( 28² - 0²) / 2 × 1.9 m
Or, s = 206.3 m
Hence, the required minimum length of the runway will be 206.3 m
482.8032 km per hr
Explanation: 300 * 1.609344 =