Physics
06.06.2022 12:51
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Aboy rides a bike with a velocity of 6 m/s on a rainy day. the rain falls down with
Aboy rides a bike with a velocity of 6 m/s on a rainy day. the rain falls down with a velocity of 8 m/s. which direction should the boy hold the umbrella to protect himself from the rain? hint, set up a right triangle and find the angle using tangent formula below you will have to use second tangent on your calculator and make sure your calculator is in degrees a• 53.13° away from the horizontal position
b• 8° from the horizontal position
c• 36.87° away from the horizontal position
d• 48.59° away from the horizontal position
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b• 8° from the horizontal position
c• 36.87° away from the horizontal position
d• 48.59° away from the horizontal position
Dallas6797
4,6(51 marks)
Answer
(A)
53.13° away from the horizontal position
ExplanationLet's suppose boy rides a bike with a velocity of 6m/s in east
→
6m/s
Let's suppose rain falls down with a velocity of 8m/s in north
↓
8m/s
Direction should the boy hold the umbrella to protect himself from the rain
/
/ ↓
/ ↓
/ ↓ 8m/s
/ x ↓
/ ↓
→ → → → → → → → →
6m/s
tanФ = opp / adj
tanФ = 8 / 6
tanФ = 4 / 3
tanФ = tan^-1(4 / 3)
tanФ = 53.13° from horizontal
jeff568463
4,5(22 marks)
Explanation:
For the reaction
H
2
O
(
l
)
+
Δ
→
H
2
O
(
g
)
WHERE BOTH PRODUCT AND REACTANT ARE AT
100
∘
C
,
Δ
H
∘
vaporization
=
40.66
⋅
k
J
⋅
m
o
l
−
1
And thus we need to assess the molar quantity of the water vaporized
Δ
H
rxn
=
5.00
⋅
g
18.01
⋅
g
⋅
m
o
l
−
1
×
40.66
⋅
k
J
⋅
m
o
l
−
1
=11.3 kJ
For the reaction
H
2
O
(
l
)
+
Δ
→
H
2
O
(
g
)
WHERE BOTH PRODUCT AND REACTANT ARE AT
100
∘
C
,
Δ
H
∘
vaporization
=
40.66
⋅
k
J
⋅
m
o
l
−
1
And thus we need to assess the molar quantity of the water vaporized
Δ
H
rxn
=
5.00
⋅
g
18.01
⋅
g
⋅
m
o
l
−
1
×
40.66
⋅
k
J
⋅
m
o
l
−
1
=11.3 kJ
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