Abody moving with a velocity of 20 m/s begins to accelerate at 3 m/s2. how far does

Initial velocity = 20m/s
Accelerations = 3m/s^2
Time taken = 5s

Using second equation of motion
ut+(1/2)at^2

Where, s is the distance covered by the body
u is initial velocity
a is acceleration and t is time taken by that body

= (20)(5)+(1/2)(3)(5)^2
=100 + 37.5
= 137.5

So, the total distance covered by the body in next 5s would be 137.5m

lo

Explanation: