41.1%
Explanation:
First write the balanced reaction:
CaCO₃ + H₂SO₄ → CaSO₄ + H₂O + CO₂
Now calculate the theoretical yield:
49.3 g CaCO₃ × (1 mol CaCO₃ / 100 g CaCO₃) = 0.493 mol CaCO₃
0.493 mol CaCO₃ × (1 mol H₂O / 1 mol CaCO₃) = 0.493 mol H₂O
0.493 mol H₂O × (18 g H₂O / mol H₂O) = 8.87 g H₂O
Now calculate the % yield:
3.65 g H₂O / 8.87 g H₂O × 100% = 41.1%
Explanation:
MM: 100.09 18.02
CaCO₃ + H₂SO₄ ⟶ CaSO₄ + H₂O + CO₂
m/g: 49.3 3.65
1. Theoretical yield
(a) Moles of CaCO₃
(b) Moles of H₂O
(c) Theoretical mass of H₂O
(d) Percent yield
Triagonal bypyramid would be the answer in this case.