Physics

23.07.2021 21:48

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A15 kg child experiences an acceleration of 0.25 m/s2 as she is pulled 1.7 m horizontally

A15 kg child experiences an acceleration of 0.25 m/s2 as she is pulled 1.7 m horizontally across the floor by her sister. what is the change in the child's kinetic energy?

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joannakawata6

4,6(39 marks)

Is it the acceleration is 0.25 m/s^2because you didn't put anything. So supposing this is true.
v^2 = u^2 + 2as v^2 = 0^2 + 2 (0.25) (1.7) v = 0.922 m/s
K = 0.5 mv^2 K = 0.5 x 15 x 0.922 K = 6.915 J
change in kinetic energy is computed by Wnett Wnett = 0.5mv^2 - 0.5mu^2 where = 0 Wnett = 6.915 J

leyslebravo7117

5,0(82 marks)

${ \bf{momentum = mass \times velocity}} \\ \\ { \tt{35 = m \times 10}} \\ { \tt{mass = 3.5 \: kg}}$

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A15 kg child experiences an acceleration of 0.25 m/s2 as she is pulled 1.7 m horizontally

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