First, calculate the acceleration of the bullet by making use of the second law of motion by Newton which can be translated in equation as,
F = m x a
Solving for a,
a = F/m
Substituting the known values,
a = (200 N)/(0.025 kg) = 8000 m/s²
The maximum velocity of the bullet is the product of the acceleration and the given time.
v = (8000 m/s²)(0.1 s) = 800 m/s
800 m/s
B they are equal and and act in opposite directions