A wire 2.80 m in length carries a current of 4.20 A in a region where a uniform

.

F = 3.0576sinθ

For any value of θ < 180

Explanation:

Generally, F = BILsinθ

Where,. F = magnetic force magnitude. B = magnetic Field magnitude.

L = length of wire. I = current

Therefore,

B = 0.260 T, L = 2.80 m

I = 4.20 A

: F = 0.260 × 4.20 × 2.80sinθ

∴ F = 3.0576sinθ

Neither Technician A nor Technician B.

Explanation:

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